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If 2a + 7b + 2c 16 and 2a + 3b + 2c 8 then b

WebEasy Solution Verified by Toppr Correct option is D) It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a). So, First we will do the sum of the three given polynomials, Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a) =(a+4a−a)+(3b−b−2b)+(−4c+9c+3c) =4a+8c Now, we can perform the subtraction, ∴ … WebSee a solution process below: Explanation: First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly: 4a+ 3b −8c −2a+ b− 4c …

A-4B+2C=16, 2A+7B-5C=23,find A+B-c= - Brainly.in

WebA-4B+ 2C=16, 2A+ 7B-5C=83, then A +B-C=? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. WebDetermine the angle between vectors a and b ( a ≠ 0, b ≠ 0) if a + 3 b is perpendicular to 2 a − b and a + 7 b is perpendicular to 2 a + b. I've done this: ( a + 3 b) ⋅ ( 2 a − b) = 0 … 5 a ⋅ b = 3 b ⋅ b − 2 a ⋅ a ( a + 7 b) ⋅ ( 2 a + b) = 0 ⋯ 15 a ⋅ b = − 2 a ⋅ a − 7 b ⋅ b which gives me: a ⋅ b = ( − ( b ⋅ b + a ⋅ a)) / 5 hair and makeup wellington https://beaumondefernhotel.com

If 2A:3B=5:6 and 3B:2C=36, then what is A:C? - Quora

WebGiven equations 2a + 7b+2c=16 and 2a + 3b +2c= 8, you want to know the value of b. Solution. The coefficients of 'a' and 'c' are the same in the two equations, so we can … WebTour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site Web27 aug. 2024 · Answer: -2a + 2c Step-by-step explanation: The situation is saying that subtract 4a-3b+2c from 2a-3b+4c. (2a-3b+4c) - (4a - 3b +2c) Subtract by terms -2a + 2c Advertisement brownen0932 Answer: 2a-6b+6c Step-by-step explanation: Combine like terms Advertisement Advertisement hair and malnutrition

If 3A=2b=5c, then find A:B:C? - Quora

Category:If A - 2B = 1 - 2 3 0 and 2A - 3B = - 3 3 1 - 1 , then B - Toppr Ask

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If 2a + 7b + 2c 16 and 2a + 3b + 2c 8 then b

3.1 If A and B are two given matrices, find 2A-3B - YouTube

WebOriginally Answered: If 2A = 3B and 4B = 5C then what is the ratio of A:C? 2A = 3B means B = 2A/3 …… (1) 4B = 5C means B = 5C/4 ……. (2) Now we can always write B = B … Web3.1 If A and B are two given matrices, find 2A-3B - YouTube 0:00 / 2:26 CLASS 12 : CONTINUITY, DIFFERENTIABILITY, INVERSE TRIGONOMETRIC FUNCTIONS, …

If 2a + 7b + 2c 16 and 2a + 3b + 2c 8 then b

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Web11 mei 2024 · tegers and verify that lcm hcf =product of the two numbers.(i) 26 and 91(ii) 510 and 92(iii) 336 and 543. find the lcm and hcf of the following integers by applying the prime factorisationmethod(i) 12, 15 and 21 (ii) 17,23 and 29(iii) 8, 9 and 254. given that hcf (306, 657)=9, find lcm (306, 657).5. check whether 6" can end with the digit 0 for ...

WebSolution Verified by Toppr Correct option is B) The balanced chemical reaction is A+2B C. 5 moles of A will react with 15×2=10 moles of B. However, only 8 moles of B are present. Thus, B is the limiting reagent. Hence, 8 moles of B will give 28×1=4 moles of C. Solve any question of Some Basic Concepts of Chemistry with:- Patterns of problems > Web3a-b-2c=8;2a-b+3c=10;a+2b+5c=6 Solution : {a,b,c} = {3,-1,1} System of Linear Equations entered : [1] 3a - b - 2c = 8 [2] 2a - b + 3c = 10 [3] a + 2b + 5c = 6 Solve by Substitution : …

Web13 apr. 2024 · Lattice-oxygen redox is pivotal for high oxygen evolution reaction (OER) activity. Here, LiNiO2, a unary 3d-transition metal oxide catalyst, exhibits superefficient activity during the OER due to ... Web30 mrt. 2024 · Their corresponding elements are equal 2a + b = 4 5c d = 11 a 2b = 3 4c + 3d = 24 Solving these equations Solving (1) 2a + b = 4 b = 4 2a Solving (3) a 2b = 3 Putting b = 4 2a a 2 (4 2a) = -3 a 8 + 4a = -3 a + 4a = -3 + 8 5a = 5 a = 5/5 a = 1 From (1) 2a + b = 4 Putting a = 1 2 (1) + b = 4 2 + b = 4 b = 4 2 b = 2 From (2) 5c d = 11 5c = 11 + d 5c …

WebOriginally Answered: If 2A = 3B and 4B = 5C then what is the ratio of A:C? 2A = 3B means B = 2A/3 …… (1) 4B = 5C means B = 5C/4 ……. (2) Now we can always write B = B Now replace LHS with equation (1) and RHS with equation (2), i.e 2A/3 = 5C/4 4* (2A) = 3* (5C) 8A = 15C A/C = 15/8 So A:C = 15 : 8 347 7 Sponsored by Aspose

Web2 nov. 2024 · Step-by-step explanation: Given equations 2a + 7b+2c=16 and 2a + 3b +2c= 8, you want to know the value of b. Solution The coefficients of 'a' and 'c' are the same in the two equations, so we can eliminate those variables by … hair and makeup wetherill parkWebCorrect option is B) Given , A−2B=[13−20] ⇒2A−4B=[26−40] ..... (i) Also given, 2A−3B=[−31 3−1] .... (ii) Subtracting (i) from (ii), we get. B=[−5−5 7−1] Solve any question of Matrices … brand\u0027s essence of chicken priceWeb7a- (5b- (4c-3 (a+3b-2c))) Final result : 2 • (2a - 7b + 5c) Step by step solution : Step 1 :Equation at the end of step 1 : 7a - (5b - (4c - 3 • (a + 3b - 2c))) Step 2 : Step 3 :Pulling … hair and makeup windsorWeba3+a2+2ab-3b2 Final result : a3 + a2 + 2ab - 3b2 Reformatting the input : Changes made to your input should not affect the solution: (1): "b2" was replaced by "b^2". 2 more similar … hair and makeup winston salemWebAnswer (1 of 7): Yes. From the equation you have: 2A + B = 3B + A Subtract A from each side and you get: A + B = 3B Subtract B from each side and you get: A = 2B From the equation you also have: 2A + B = 10 Since we have shown that A = 2B, substitute 2B for A: 2 * 2B + B = 10 -> 4B + B ... hair and makeup west aucklandWeb(i) a + b and 2a + 3b It can be written as = a + b + 2a + 3b So we get = a + 2a + b + 3b = 3a + 4b (ii) 2x + y and 3x – 4y It can be written as = 2x + y + 3x – 4y So we get = 2x + 3x + y – 4y = 5x – 3y (iii) -3a + 2b and 3a + b It can be written as = -3a + 2b + 3a + b So we get = -3a + 3a + 2b + b = 3b (iv) 4 + x, 5 – 2x and 6x It can be written as hair and makeup wedding timelineWeb1 nov. 2024 · Step-by-step explanation: Given equations 2a + 7b+2c=16 and 2a + 3b +2c= 8, you want to know the value of b. Solution The coefficients of 'a' and 'c' are the same in … hair and matthews american legion post 32